Kirchhoff's Voltage Law (KVL) / Mesh Analysis
Q) Find the current flowing through 1 Ω resistance by using Kirchhoff’s voltage law / Mesh analysis.
For Mesh 1
130-0.2I_1-0.2I_1+0.2I_2-110=0
-0.4I_1+0.2I_2=-20 \ldots\ldots (1)
For Mesh 2
-I_2+110-0.2I_2+0.2I_1-0.2I_2=0
0.2I_1-1.4I_2=-110 \ldots\ldots (2)
I_1 = 96.1538 A (clockwise)
I_2 = 92.3076 A (clockwise)
\therefore current flowing through 1 Ω resistor is 92.3076 A.
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